1Z0-061 Exam - Oracle Database 12c SQL Fundamentals

certleader.com

Q1. You need to create a table for a banking application. One of the columns in the table has the following requirements: 

1) You want a column in the table to store the duration of the credit period. 

2) The data in the column should be stored in a format such that it can be easily added and subtracted with date data type without using conversion functions. 

3) The maximum period of the credit provision in the application is 30 days. 

4) The interest has to be calculated for the number of days an individual has taken a credit for. 

Which data type would you use for such a column in the table? 

A. DATE 

B. NUMBER 

C. TIMESTAMP 

D. INTERVAL DAY TO SECOND 

E. INTERVAL YEAR TO MONTH 

Answer:

Q2. View the Exhibits and examine products and sales tables. 

You issue the following query to display product name and the number of times the product has been sold: 

What happens when the above statement is executed? 

A. The statement executes successfully and produces the required output. 

B. The statement produces an error because item_cnt cannot be displayed in the outer query. 

C. The statement produces an error because a subquery in the from clause and outer-joins cannot be used together. 

D. The statement produces an error because the group by clause cannot be used in a subquery in the from clause. 

Answer:

Q3. You issued the following command: 

SQL> DROP TABLE employees; 

Which three statements are true? 

A. All uncommitted transactions are committed. 

B. All indexes and constraints defined on the table being dropped are also dropped. 

C. Sequences used in the employees table become invalid. 

D. The space used by the employees table is reclaimed immediately. 

E. The employees table can be recovered using the rollback command. 

F. The employees table is moved to the recycle bin. 

Answer: B,C,F 

Reference: http://www.sqlcourse.com/drop.html 

Q4. View the Exhibit and examine the structure of the customers table. 

NEW_CUSTOMERS is a new table with the columns CUST_ID, CUST_NAME and CUST_CITY that have the same data types and size as the corresponding columns in the customers table. 

Evaluate the following insert statement: The insert statement fails when executed. 

What could be the reason? 

A. The values clause cannot be used in an INSERT with a subquery. 

B. Column names in the NEW_CUSTOMERS and CUSTOMERS tables do not match. 

C. The where clause cannot be used in a subquery embedded in an INSERT statement. 

D. The total number of columns in the NEW_CUSTOMERS table does not match the total number of columns in the CUSTOMERS table. 

Answer:

Explanation: 

Copying Rows from Another Table 

Write your INSERT statement with a subquery: 

Do not use the VALUES clause. 

Match the number of columns in the INSERT clause to those in the subquery. 

Inserts all the rows returned by the subquery in the table, sales_reps. 

Q5. Examine the types and examples of relationships that follow: 

1. One-to-one a) Teacher to students 

2. One-to-many b) Employees to Manager 

3. Many-to-one c) Person to SSN 

4. Many-to-many d) Customers to products 

Which option indicates the correctly matched relationships? 

A. 1-a, 2-b, 3-c, and 4-d 

B. 1-c, 2-d, 3-a, and 4-b 

C. 1-c, 2-a, 3-b, and 4-d 

D. 1-d, 2-b, 3-a, and 4-c 

Answer:

Q6. Which three tasks can be performed using SQL functions built into Oracle Database? 

A. Displaying a date in a nondefault format 

B. Finding the number of characters in an expression 

C. Substituting a character string in a text expression with a specified string 

D. Combining more than two columns or expressions into a single column in the output 

Answer: A,B,C 

Q7. Examine the structure of the orders table: 

You want to find the total value of all the orders for each year and issue the following command: 

Which statement is true regarding the outcome? 

A. It executes successfully and gives the correct output. 

B. It gives an error because the TO_CHAR function is not valid. 

C. It executes successfully but does not give the correct output. 

D. It gives an error because the data type conversion in the SELECT list does not match the data type conversion in the GROUP BY clause. 

Answer:

Q8. You need to display the first names of all customers from the customers table that contain the character 'e' and have the character 'a' in the second last position. 

Which query would give the required output? 

A. Option A 

B. Option B 

C. Option C 

D. Option D 

Answer:

Explanation: 

The SUBSTR(string, start position, number of characters) function accepts three parameters and returns a string consisting of the number of characters extracted from the source string, beginning at the specified start position: 

substr('http://www.domain.com', 12, 6) = domain 

The position at which the first character of the returned string begins. 

When position is 0 (zero), then it is treated as 1. 

When position is positive, then the function counts from the beginning of string to find the first character. 

When position is negative, then the function counts backward from the end of string. substring_length 

The length of the returned string. SUBSTR calculates lengths using characters as defined by the input character set. SUBSTRB uses bytes instead of characters. SUBSTRC uses 

Unicode complete characters. 

SUBSTR2 uses UCS2 code points. SUBSTR4 uses UCS4 code points. 

When you do not specify a value for this argument, then the function 

The INSTR(source string, search item, [start position], [nth occurrence of search item]) function returns a number that represents the position in the source string, beginning from the given start position, where the nth occurrence of the search item begins: 

instr('http://www.domain.com', '.', 1, 2) = 18 

Q9. Evaluate the following SQL commands: 

The command to create a table fails. Identify the two reasons for the SQL statement failure? 

A. You cannot use SYSDATE in the condition of a check constraint. 

B. You cannot use the BETWEEN clause in the condition of a check constraint. 

C. You cannot use the NEXTVAL sequence value as a default value for a column. 

D. You cannot use ORD_NO and ITEM_NO columns as a composite primary key because ORD_NO is also the foreign key. 

Answer: A,C 

Explanation: 

CHECK Constraint The CHECK constraint defines a condition that each row must satisfy. The condition can use the same constructs as the query conditions, with the following exceptions: References to the CURRVAL, NEXTVAL, LEVEL, and ROWNUM pseudocolumns Calls to SYSDATE, UID, USER, and USERENV functions Queries that refer to other values in other rows A single column can have multiple CHECK constraints that refer to the column in its definition. There is no limit to the number of CHECK constraints that you can define on a column. CHECK constraints can be defined at the column level or table level. CREATE TABLE employees (... Salary NUMBER(8, 2) CONSTRAINT emp_salary_min CHECK (salary > 0), 

Q10. You want to create a table employees in which the values of columns EMPLOYEES_ID and LOGIN_ID must be unique and not null. Which two SQL statements would create the required table? 

A. Option A 

B. Option B 

C. Option C 

D. Option D 

E. Option E 

F. Option F 

Answer: D,E