Q1. An nmap command that includes the host specification of 202.176.56-57.* will scan _______ number of hosts.
A. 2
B. 256
C. 512
D. Over 10,000
Answer: C
Explanation: The hosts with IP address 202.176.56.0-255 & 202.176.56.0-255 will be scanned (256+256=512)
Q2. You have the SOA presented below in your Zone. Your secondary servers have not been able to contact your primary server to synchronize information. How long will the secondary servers attempt to contact the primary server before it considers that zone is dead and stops responding to queries?
collegae.edu.SOA,cikkye.edu ipad.college.edu. (200302028 3600 3600 604800 3600)
A. One day
B. One hour
C. One week
D. One month
Answer: C
Explanation: The numbers represents the following values: 200302028; se = serial number 3600; ref = refresh = 1h 3600; ret = update retry = 1h 604800; ex = expiry = 1w 3600; min = minimum TTL = 1h
Q3. Which of the following is the best way an attacker can passively learn about technologies used in an organization?
A. By sending web bugs to key personnel
B. By webcrawling the organization web site
C. By searching regional newspapers and job databases for skill sets technology hires need to possess in the organization
D. By performing a port scan on the organization's web site
Answer: C
Explanation: Note: Sending web bugs, webcrawling their site and port scanning are considered "active" attacks, the question asks "passive"
Q4. What is the most common vehicle for social engineering attacks?
A. Email
B. Direct in person
C. Local Area Networks
D. Peer to Peer Networks
Answer: B
Explanation: All social engineering techniques are based on flaws in human logic known as cognitive biases.
Topic 10, Session Hijacking
322. Bob is going to perform an active session hijack against company. He has acquired the target that allows session oriented connections (Telnet) and performs sequence prediction on the target operating system. He manages to find an active session due to the high level of traffic on the network.
So, what is Bob most likely to do next?
A. Take over the session.
B. Reverse sequence prediction.
C. Guess the sequence numbers.
D. Take one of the parties’ offline.
Q5. Choose one of the following pseudo codes to describe this statement:
If we have written 200 characters to the buffer variable, the stack should stop because it cannot hold any more data.
A. If (I > 200) then exit (1)
B. If (I < 200) then exit (1)
C. If (I <= 200) then exit (1)
D. If (I >= 200) then exit (1)
Answer: D
Q6. According to the CEH methodology, what is the next step to be performed after footprinting?
A. Enumeration
B. Scanning
C. System Hacking
D. Social Engineering
E. Expanding Influence
Answer: B
Explanation: Once footprinting has been completed, scanning should be attempted next.
Scanning should take place on two distinct levels: network and host.
Q7. Maintaining a secure Web server requires constant effort, resources, and vigilance from an organization. Securely administering a Web server on a daily basis is an essential aspect of Web server security.
Maintaining the security of a Web server will usually involve the following steps:
1. Configuring, protecting, and analyzing log files
2. Backing up critical information frequently
3. Maintaining a protected authoritative copy of the organization's Web content
4. Establishing and following procedures for recovering from compromise
5. Testing and applying patches in a timely manner
6. Testing security periodically.
In which step would you engage a forensic investigator?
A. 1
B. 2
C. 3
D. 4
E. 5
F. 6
Answer: D
Q8. On wireless networks, SSID is used to identify the network. Why are SSID not considered to be a good security mechanism to protect a wireless networks?
A. The SSID is only 32 bits in length.
B. The SSID is transmitted in clear text.
C. The SSID is the same as the MAC address for all vendors.
D. The SSID is to identify a station, not a network.
Answer: B
Explanation: The SSID IS constructed to identify a network, it IS NOT the same as the MAC address and SSID’s consists of a maximum of 32 alphanumeric characters.
Q9. This IDS defeating technique works by splitting a datagram (or packet) into multiple fragments and the IDS will not spot the true nature of the fully assembled datagram. The datagram is not reassembled until it reaches its final destination. It would be a processor-intensive tasks for an IDS to reassemble all fragments itself and on a busy system the packet will slip through the IDS onto the network.
What is this technique called?
A. IP Fragmentation or Session Splicing
B. IP Routing or Packet Dropping
C. IDS Spoofing or Session Assembly
D. IP Splicing or Packet Reassembly
Answer: A
Explanation: The basic premise behind session splicing, or IP Fragmentation, is to deliver the payload over multiple packets thus defeating simple pattern matching without session reconstruction. This payload can be delivered in many different manners and even spread out over a long period of time. Currently, Whisker and Nessus have session splicing capabilities, and other tools exist in the wild.
Q10. XSS attacks occur on Web pages that do not perform appropriate bounds checking on data entered by users. Characters like < > that mark the beginning/end of a tag should be converted into HTML entities.
What is the correct code when converted to html entities?
A. Option A
B. Option B
C. Option C
D. Option D
Answer: D